Word Problems Involving Money

Word Problems Involving Money - h1014v1_166

Mathematics Volume 1 of 2
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Algebra WORD PROBLEMS x = .55

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.65 x = 7 Solving for the other unknowns: 2x = 2(7) 2x = 14 x + 5 = 7 + 5 x + 5 = 12 Answers: Number of Nickels = 7 Number of Dimes = 12 Number of Quarters = 14 Step 5. The number of quarters is twice the number of nickels. 2(7) = 14 The number of dimes is five more than the number of nickels. 7 + 5 = 12 The total value is .05. 7(

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.05) + 12(

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.10) + 14(

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.25) =

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.35 + ||content|| .20 + .50 = .05 Thus, the answers check. Rev. 0 Page 53 MA-02

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