Po 2t /DT
0.10 sec1 0.00249
Reactor Theory (Reactor Operations)
Doubling time (DT) = (ln 2)
= stable reactor period
= natural logarithm of 2
When the doubling time is known, the power level change from P is given by the following
= time interval of transient
= doubling time
The following example problems reinforce the concepts of period and startup rate.
A reactor has a
of 0.10 sec and an effective delayed neutron fraction of 0.0070. If
k is equal to 1.0025, what is the stable reactor period and the SUR?
First solve for reactivity using Equation (3-5).
Use this value of reactivity in Equation (4-9) to calculate reactor period.