DC CIRCUIT ANALYSIS Basic DC Theory Rearrange and combine like terms in the Loop 2 equation. 200  I₂ 200  I₁ 100  I₂ 10 40 200  I₁ 300  I₂ 50 Multiplying the Loop 1 equation by 3, and add it to the Loop 2 equation. 3(   125  I₁ 100  I₂ 1) 375  I₁ 300I₂ 3 200  I₂ 300I₂ 50 175  I₁ 47 Solving for I₁: 175  I₁ 47 I₁ 47 175 0.2686  amp 268.6  mA Solving for I₂  using the Loop 1 equation: 125  (0.2686) 100  I₂ 1 100  I₂ 1 33.58 I₂ 34.58 100 I₂ 0.3458  amp 345.8  mA The current flow through R₁  (50W) is I₁.   The current flow through R₂(100W) is I₂, and through R₃(200W) is I₂  - I₁: I₃ I₂ I₁ 345.8  mA 268.6  mA I₃ I₂ I₁ 77.2  mA ES-02 Page 52 Rev. 0