SIMULTANEOUS EQUATIONS
Algebra
Substitute the value for x into the other equation:
5 (2 - 4y) + 3y = -1
3
10 - 20y + 3y = -1
3
10 - 20y + 9y = -1
3
3
10 - 11y = -1
3
-11y = -11
3
y = 3
Substitute y = 3 into the first equation:
3x + 4(3) = 6
3x
= -6
x = -2
Check the solution by substituting x = -2 and y = 3 into the original equations.
3x + 4y = 6
5x + 3y = -1
3(-2) + 4(3) = 6
5(-2) + 3(3) = -1
-6 + 12 = 6
-10 + 9 = -1
6 = 6
-1 = -1
Thus, the solution checks.
MA-02
Page 40
Rev. 0
