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Log Rules - h1014v1_179
Log Rules - h1014v1_181
Mathematics Volume 1 of 2
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LOGARITHMS
Algebra
Example 1:
y
=
gt
2
where
g
= 32
1
2
Solution:
y
= 16
t
2
Find
y
for
t
= 10 using logs.
log
10
y
= log
10
(16
t
2
)
log
10
y
= log
10
16 + log
10
t
2
log
10
y
= log
10
16 + (2 log
10
t
)
log
10
y
= 1.204 + 2 log
10
10
log
10
y
= 1.204 + 2 x 1
log
10
y
= 3.204
but this means 10
3.204
=
y
y
= 1600
Example 2:
Calculate log
10
2 - log
10
3.
Solution:
Rule 2.
log
10
(
A/B
): log
10
A
- log
10
B
log
10
2 - log
10
3
= log
10
(2/3)
= log
10
(.667)
= -0.176
MA-02
Page 66
Rev. 0
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