LOGARITHMS
Algebra
Example 1:
y =
gt2 where g = 32
1
2
Solution:
y = 16 t2
Find y for t = 10 using logs.
log10y = log10 (16 t2)
log10y = log10 16 + log10 t2
log10y = log10 16 + (2 log10 t)
log10y = 1.204 + 2 log10 10
log10y = 1.204 + 2 x 1
log10y = 3.204
but this means 103.204 = y
y = 1600
Example 2:
Calculate log10 2 - log10 3.
Solution:
Rule 2.
log10 (A/B): log10 A - log10 B
log10 2 - log10 3
= log10 (2/3)
= log10 (.667)
= -0.176
MA-02
Page 66
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