Algebra
WORD PROBLEMS
Solving for the other unknowns:
= Time Taken by Faster Plane (in hours)
x
525
x
525
2100
525
= 4 hours
x
525
= Time Taken by Slower Plane (in hours)
x
350
x
350
2100
350
= 6 hours
x
350
Answers:
Distance Traveled = 2100 miles
Time Taken by Faster Plane = 4 hours
Time Taken by Slower Plane = 6 hours
Step 5.
The faster plane takes 2 hours less to complete the trip than the
slower plane.
6 hours - 2 hours = 4 hours
Thus, the answer checks.
Example 2:
It takes a man 4 hours to reach a destination 1325 miles from his home. He
drives to the airport at an average speed of 50 miles per hour, and the average
speed of his plane trip is 500 miles per hour. How far does he travel by each
mode of transportation?
Solution:
Step 1.
Let x = Distance Traveled by Car (in miles)
Step 2.
Then,
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