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Word Problems Involving Money - h1014v1_165
Word Problems Involving Money - h1014v1_167

Mathematics Volume 1 of 2
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WORD PROBLEMS Algebra Step 5. The  price  of  children’s  tickets  is  one-half  the  price  of  adults’ tickets. 1 2 (.00) ||content|| .50 The gross is ,000. 4,000(.00) + 2,000( ||content|| .50) = ,000 + ,000 = ,000 Thus, the answers check. Example 2: A  collection  of  coins  consists  of  nickels,  dimes,  and  quarters.   The  number  of quarters is twice the number of nickels, and the number of dimes is five more than the number of nickels.   If the total amount of money is .05, how many of each type of coin are in the collection? Solution: Step 1. Let  x  = Number of Nickels Step 2. Then, 2x = Number of Quarters x + 5 = Number of Dimes Step 3. Total Value = (Number of Nickels)(Value of a Nickel) + (Number of  Dimes)(Value  of  a  Dime)  +  (Number  of  Quarters)(Value  of  a Quarter) .05 = (x)(
||content||
.05) + (x + 5)(
||content||
.10) + (2x)(
||content||
.25)
Step 4. Solving for x: .05 = (x)(
||content||
.05) + (x + 5)(
||content||
.10) + (2x)(
||content||
.25)
.05 =
||content||
.05x +
||content||
.10x +
||content||
.50 +
||content||
.50x
.05 =
||content||
.65x +
||content||
.50
||content||
.65x = .05 -
||content||
.50
||content||
.65x = .55
MA-02 Page 52 Rev. 0









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