Figure 14 F = 50 lbf at 53

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Vectors VECTORS: RESULTANTS AND COMPONENTS Rev. 0 Page 13 CP-02 Figure 14 F = 50 lbf at 53 R o Example 1: Determine the component vectors, F and F , for F = 50 lbf at 53 in Figure 14. x y R o Use trigonometric functions. F is calculated as follows: x cos = adjacent/hypotenuse cos = F /F or F = F cos x R x R F = (50)(cos53 ) x o F = (50)(0.6018) x F = 30 lbf on x-axis x F is calculated as follows: y sin = opposite/hypotenuse sin = F /F or F = F sin y R y R F = (F )(sin ) y R F = (50)(sin 53 ) y o F = (50)(0.7986) y F = 40 lbf on y-axis y Therefore, the components for F are F = 30 lbf at 0 and F = 40 lbf at 90 . Note that this result R x y o o is identical to the result obtained using the graphic method.

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