Figure 7 Free-Body Diagram

Classical Physics - Physics theories and other related topics
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' F_x T ¹x T ²x T ³x 0 ' F_y T ¹y T ²y T ³y 0 ' F_y (T₁ sin30- ) (T₂ sin180- ) (T₃ sin270- ) 0 (T₁)(0.5) (T₂)(0) (125 lbf)( 1) 0 0.5T₁ 125 lbf 0 0.5T₁ 125 lbf T₁ 250 lbf FORCE EQUILIBRIUM Application of Newton's Laws CP-04 Page 14 Rev. 0 Figure 7 Free-Body Diagram The tension in a cable is the force transmitted by the cable. The tension at any point in the cable can be measured by cutting a suitable length from it and inserting a spring scale. Solution: Since the object and its supporting cables are motionless (i.e., in equilibrium), we know that the net force acting on the intersection of the cables is zero. The fact that the net force is zero tells us that the sum of the x-components of T , T , and T is zero, and the 1 2 3 sum of the y-components of T , T , and T is zero. 1 2 3 The tension T is equal to the weight of the object, 125 lbf. The x and y components of the 3 tensions can be found using trigonometry (e.g., sine function). Substituting known values into the second equation above yields the following. A simpler method to solve this problem involves assigning a sign convention to the free-body diagram and examining the direction of the forces.

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