Thermodynamics SECOND LAW OF THERMODYNAMICSSolution:where = entropy added to the systemmsinpmsoutppm (soutsin)sin= 1.7088 Btu/lbm -°R (from steam tables)sout= 1.8158 Btu/lbm°R (from steam tables)= Btu/lbm-oRp/ msoutsin1.81581.7088= 0.107 Btu/lbm -°Rp/ m= 10,000 (0.107)p= 1070 Btu/lbm -°R. = entropy added to the systempIt should always be kept in mind that the Second Law of Thermodynamics gives an upper limit(which is never reached in physical systems) to how efficiently a thermodynamic system canperform. A determination of that efficiency is as simple as knowing the inlet and exittemperatures of the overall system (one that works in a cycle) and applying Carnot’s efficiencyequation using these temperatures in absolute degrees.DiagramsofIdealandRealProcessesAny ideal thermodynamic process can be drawn as a path on a property diagram, such as a T-sor an h-s diagram. A real process that approximates the ideal process can also be representedon the same diagrams (usually with the use of dashed lines).In an ideal process involving either a reversible expansion or a reversible compression, theentropy will be constant. These isentropic processes will be represented by vertical lines oneither T-s or h-s diagrams, since entropy is on the horizontal axis and its value does not change.A real expansion or compression process operating between the same pressures as the idealprocess will look much the same, but the dashed lines representing the real process will slantslightly towards the right since the entropy will increase from the start to the end of the process.Figures 24 and 25 show ideal and real expansion and compression processes on T-s and h-sdiagrams.Rev. 0 Page 77 HT-01
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