MATRICES AND DETERMINANTS
Higher Concepts of Mathematics
Solution:
2
3
1
10
2
2
1
1
2
x =
2
3
1
1
2
2
3
1
2
2
2
1
1
10
2
3
1
2
y =
2
3
1
1
2
2
3
1
2
2
3
2
1
2
10
3
1
1
z =
2
3
1
1
2
2
3
1
2
Expanding the top matrix for x using the elements in the bottom row gives:
1
3
1
2
2
( 1)
2
1
10
2
( 2)
2
3
10
2
1 (6
2)
( 1) (4
10)
( 2) ( 4
30)
4
6
52
42
MA-05
Page 28
Rev. 0
